Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.4 The Product And Quotient Rules - Exercises Set 2.4 - Page 147: 2

Answer

a) $f'(x) = 12x^3+10x$ b) $f'(x)=12x^3+10x$

Work Step by Step

a) First, multiply out the expression: $f(x)=3x^4-x^2+6x^2-2=3x^4+5x^2-2$ Then, take the derivative of each term: $f'(x) = 4*3x^3+2*5x^1-0=12x^3+10x$ b) Take the derivative of the equation using Product Rule: $f'(x) = (3x^2-1)(2x+0)+(2*3x^1-0)(x^2+2)$ $=6x^3-2x+6x^3+12x=12x^3+10x$
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