Answer
$f'x=-5x^{-5}-9x^{-4}-4x^{-3}-7x^{-2}+14$
Work Step by Step
Rewrite the function
$f(x)=(2x+1)(1+\frac{1}{x})(x^{-3}+7)$
$f(x)=(2x+1+2+x^{-1})(x^{-3}+7)$
$=(2x+3+x^{-1})(x^{-3}+7)$
$=2x^{-2}+3x^{-3}+x^{-4}+14x+21+7x^{-1}$
Evaluate $f'(x)$
$f'(x)=(2x^{-2}+3x^{-3}+x^{-4}+14x+21+7x^{-1})'$
$=-4x^{-3}-9x^{-4}-5x^{-5}+14+0-7x^{-2}$
$=-5x^{-5}-9x^{-4}-4x^{-3}-7x^{-2}+14$