Answer
$f’(x) = 3x^2 $
Work Step by Step
$f(x) = (x+1)(x^2-x+1) $
$f’(x) = (1)(x^2-x+1)+(x+1)(2x-1) $
$f’(x)= x^2-x+1+2x^2-x+2x-1 $
$f’(x) = 3x^2 $
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