Answer
$F''(x)= xf''(x) + 2f'(x)$
Work Step by Step
$F'(x) = xf'(x) + (1)f(x)$
$= xf'(x) + f(x)$
$\Rightarrow F''(x) = (xf''(x) + f'(x)) + f'(x)$
$= xf''(x) + 2f'(x)$
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