Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.4 The Product And Quotient Rules - Exercises Set 2.4 - Page 147: 1

Answer

$f’(x) = 4x+1 $

Work Step by Step

$f(x) = (x+1)(2x-1) $ $f(x) =2x^2-x+2x-1 $ $f(x) = 2x^2+x-1 $ $f’(x) = 2(2)x^{(2-1)} + 1x^{(1-1)} -0 $ $f’(x) = 4x-1 $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.