Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.4 The Product And Quotient Rules - Exercises Set 2.4 - Page 147: 10

Answer

$f’(x) = 4x^3-2x $

Work Step by Step

$f(x) = (x^2+x)(x^2-x) $ $f’(x) = (2x+1)(x^2-x)+(2x-1)(x^2+x) $ $f’(x) = 2x^3-2x^2+x^2-x+2x^3+2x^2-x^2-x $ $f’(x) = 4x^3 -2x$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.