Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.5 - Finding Factors of Special Products - Exercise - Page 354: 19

Answer

$$(1+xy)(1-xy)$$

Work Step by Step

$1-x^{2}y^{2}$ This is the difference between two squares. There is a simple formula for this case: $x^{2}-y^{2}=(x+y)(x-y)$ So, applying this formula: We need to take the square of both terms. $\sqrt 1=1$ $\sqrt x^{2}y^{2}=xy$ So the answer would look like: $$(1+xy)(1-xy)$$ (One with a positive sign and one with a negative sign.)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.