Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.5 - Finding Factors of Special Products - Exercise - Page 354: 22



Work Step by Step

This is a difference between two squares, and hence $$16x^2-1=(4x-1)(4x+1).$$ One can check as follows $$(4x-1)(4x+1)=16x^2-4x+4x+1=16x^2-1 .$$
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