Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.5 - Finding Factors of Special Products - Exercise - Page 354: 12



Work Step by Step

$9x^{2}-25$ This is the difference between two squares. There is a simple formula for this case: $x^{2}-y^{2}=(x+y)(x-y)$ So, applying this formula, We need to take the square of both terms. $\sqrt 9x^{2}=3x$ $\sqrt 25=5$ So the answer would look like: $$(3x+5)(3x-5)$$ (One with a positive sign and one with a negative sign.)
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