Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.5 - Finding Factors of Special Products - Exercise - Page 354: 30

Answer

$(4-cd)(4+cd)$

Work Step by Step

This is a difference between two squares, and hence $$16-c^2d^2=(4-cd)(4+cd).$$ One can check as follows $$ (4-cd)(4+cd)=16-4cd+4cd-c^2d^2=16-c^2d^2 .$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.