Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.5 - Finding Factors of Special Products - Exercise - Page 354: 30



Work Step by Step

This is a difference between two squares, and hence $$16-c^2d^2=(4-cd)(4+cd).$$ One can check as follows $$ (4-cd)(4+cd)=16-4cd+4cd-c^2d^2=16-c^2d^2 .$$
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