Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.5 - Finding Factors of Special Products - Exercise - Page 354: 37



Work Step by Step

First, we take a common monomial factor as follows $$ 27x^2-3=3(9x^2-1) .$$ This is a difference between two squares, and hence $$ (9x^2-1)=(3x-1)(3x+1) .$$ One can check as follows $$ 3(3x-1)(3x+1)=3(9x-3x+3x-1)=3(9x^2-1)=27x^2-3 .$$
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