Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.5 - Finding Factors of Special Products - Exercise - Page 354: 3



Work Step by Step

This is a difference between two squares, and hence $$b^2-c^2=(b-c)(b+c).$$ One can check as follows $$(b-c)(b+c)=b^2-bc+bc-c^2=b^2-c^2 .$$
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