Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.5 - Finding Factors of Special Products - Exercise - Page 354: 25



Work Step by Step

This is a difference between two squares, and hence $$49x^2-25=(7x-5)(7x+5).$$ One can check as follows $$(7x-5)(7x+5)=49x^2-35x+35x-25=49x^2-25 .$$
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