Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.5 - Finding Factors of Special Products - Exercise - Page 354: 38



Work Step by Step

First, we take a common monomial factor as follows $$ 225x^4-9x^2=9x^2(25x^2-1) .$$ This is a difference between two squares, and hence $$ (25x^2-1)=(5x-1)(5x+1) .$$ One can check as follows $$ 9x^2(5x-1)(5x+1)=9x^2(25x^2-5x+5x-1)=9x^2(25x^2-1)=225x^4-9x^2 .$$
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