# Chapter 10 - Section 10.5 - Finding Factors of Special Products - Exercise - Page 354: 17

$$(7x+8y)(7x-8y)$$

#### Work Step by Step

$49x^{2}-64y^{2}$ This is the difference between two squares. There is a simple formula for this case: $x^{2}-y^{2}=(x+y)(x-y)$ So, applying this formula, We need to take the square of both terms. $\sqrt 49x^{2}=7x$ $\sqrt 64y^{2}=8y$ So the answer would look like: $$(7x+8y)(7x-8y)$$ (One with a positive sign and one with a negative sign.)

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