Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 390: 9

Answer

$\dfrac{1}{3},-2$

Work Step by Step

Given: $3x^2=2-5x$ or, $30x^2+5x-2=0$ Need to use factorization to solve the quadratic equation. This can be factorized as follows: $30x^2-x+6x-2=0$ or, $(3x-1)(x+2)=0$ Now $3x-1=0$ and $x+2=0$ Roots are $x= \dfrac{1}{3},-2$
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