Answer
$\dfrac{-1}{2},3$
Work Step by Step
Given: $2x^2-5x-3=0$
Need to use factorization to solve the quadratic equation.
This can be factorized as follows:
$2x^2+x-6x-3=0$
or, $(2x+1)(x-3)=0$
Now $2x+1=0$ and $x-3=0$
Roots are $x= \dfrac{-1}{2},3$
