Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 390: 38



Work Step by Step

Given: $x^3-2x^2-x+2=0$ or, $x^2(x-2)-1(x-2)=0$ Need to use factorization to solve the quadratic equation. This can be factorized as follows: $(x^2-1)(x-2)=0$ or, $(x-1)(x+1)(x-2)=0 $ Set each factor equal to zero, we get $x=-1,1,2$
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