Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 390: 28



Work Step by Step

Given: $(x-1)(x+4)=14$ or, $x^2+3x-18=0$ Need to use factorization to solve the quadratic equation. This can be factorized as follows: $x^2-3x+6x-18=0$ or, $(x-3)(x+6)=0$ Now, $x-3=0$ and $x+6=0$ This implies $x=3,-6$
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