Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 390: 24



Work Step by Step

Given: $4x^2=25$ or, $4x^2-25=0$ Need to use factorization to solve the quadratic equation. This can be factorized as follows: $(2x)^2-(5)^2=0$ or, $(2x+5)(2x-5)=0$ Now, $2x+5=0$ and $2x-5=0$ This implies $x=-\dfrac{5}{2},\dfrac{5}{2}$
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