Answer
$-2,8$
Work Step by Step
Given: $(x+1)^2-5(x+2)=3x+7$
or, $x^2-6x-16=0$
Need to use factorization to solve the quadratic equation.
This can be factorized as follows:
$x^2+2x-8x-16=0$
or, $(x+2)(x-8)=0 $
Now, $x+2=0$ and $x-8=0$
This implies $x=-2,8$
