Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 390: 46

Answer

$0,-2,5$

Work Step by Step

Given: $3x^3-9x^2-30x=0$ or, $3x(x^2-3x-10)=0$ Need to use factorization to solve the quadratic equation. This can be factorized as follows: $3x(x^2+2x-5x-10)=0$ or, $3x(x+2)(x-5)=0$ Set each factor equal to zero, we get $3x=0 \implies x=0$ Now, $x+2=0$, and $x-5=0$ Thus, $x=0,-2,5$
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