Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 390: 40

Answer

$-4,4,-2$

Work Step by Step

Given: $x^3+2x^2=16x-32$ or, $x^3+2x^2-16x+32=0$ or, $x^2(x+2)-16(x+2)=0$ Need to use factorization to solve the quadratic equation. This can be factorized as follows: $(x^2-16)(x+2)=0$ or, $(x-4)(x+4)(x+2)=0 $ Set each factor equal to zero, we get $x=-4,4,-2$
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