Work Step by Step
Given: $x(x-3)=18$ or, $x^2-3x-18=0$ Need to use factorization to solve the quadratic equation. This can be factorized as follows: $x^2+3x-6x-18=0$ or, $(x+3)(x-6)=0$ Now, $x+3=0$ and $x-6=0$ This implies $x=-3,6$
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