Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 390: 8



Work Step by Step

Given: $70x^2=30x-8$ or, $70x^2-30x+8=0$ Need to use factorization to solve the quadratic equation. This can be factorized as follows: $70x^2-28x-2x+8=0$ or, $(7x-2)(x-4)=0$ Now $7x-2=0$ and $x-4=0$ Roots are $x= \dfrac{2}{7},4$
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