Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 390: 10



Work Step by Step

Given: $5x^2=2+3x$ or, $5x^2-3x-2=0$ Need to use factorization to solve the quadratic equation. This can be factorized as follows: $5x^2+2x-5x-2=0$ or, $(5x+2)(x-1)=0$ Now $5x+2=0$ and $x-1=0$ Roots are $x= \dfrac{-2}{5},1$
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