Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 9



Work Step by Step

Need to find the first four terms of $a_n=\dfrac{2n}{n+4}$ when $n=1,2,3,4$ Thus, $a_1=\dfrac{2(1)}{1+4}=\dfrac{2}{5}$ $a_2=\dfrac{2(2)}{2+4}=\dfrac{4}{6}=\dfrac{2}{3}$ $a_3=\dfrac{2(3)}{3+4}=\dfrac{6}{7}$ $a_4=\dfrac{2(4)}{4+4}=1$ Hence, the first four terms are: $\dfrac{2}{5},\dfrac{2}{3},\dfrac{6}{7},1$
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