Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 23



Work Step by Step

Since, we have $\sum_{i=1}^{4}(\dfrac{-1}{2})^i=(\dfrac{-1}{2})^1+(\dfrac{-1}{2})^2+(\dfrac{-1}{2})^3+(\dfrac{-1}{2})^4$ or, $=\dfrac{-1}{2}+\dfrac{1}{4}-\dfrac{1}{8}+\dfrac{1}{16}$ Hence, we get $=\dfrac{-5}{16}$
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