Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 11



Work Step by Step

Need to find the first four terms of $a_n=\dfrac{(-1)^{n+1}}{2^n-1}$ when $n=1,2,3,4$ Thus, $a_1=\dfrac{(-1)^{1+1}}{2^1-1}=1$ $a_2=\dfrac{(-1)^{2+1}}{2^2-1}=\dfrac{-1}{3}$ $a_3=\dfrac{(-1)^{3+1}}{2^3-1}=\dfrac{1}{7}$ $a_4=\dfrac{(-1)^{4+1}}{2^4-1}=\dfrac{-1}{15}$ Hence, the first four terms are: $1,\dfrac{-1}{3},\dfrac{1}{7},\dfrac{-1}{15}$
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