Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 15



Work Step by Step

Need to find the first four terms of $a_n=2(n+1)!$ when $n=1,2,3,4$ Thus, $a_1=2(1+1)!=4$ $a_2=2(2+1)!=2.(3.2.1)=12$ $a_3=2(3+1)!=2($ $a_4=2(4+1)!=2($ Hence, the first four terms are: $4,12,48,240$
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