Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 1

Answer

$a_1=5 \\a_2=8 \\a_3 = 11 \\a_4 = 14$

Work Step by Step

To find the first four terms of the given sequence, substitute 1, 2, 3, and 4 to $n$, respectively, then simplify. $a_1 = 3(1) + 2 = 3 + 2 = 5 \\a_2 = 3(2) + 2 = 6 + 2 = 8 \\a_3 = 3(3) + 2 = 9+2 = 11 \\a_4 = 3(4) +2 = 12+2 = 14$
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