Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 20



Work Step by Step

Since, we have $\sum_{i=1}^{5}(i^3)=(1^3+2^3+3^3+4^3+5^3)$ or, $=1+8+27+64+125$ Hence, we get $=225$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.