Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 56



Work Step by Step

Since, we have from the graph: $\sum_{i=1}^{5}a_i^2-\sum_{i=1}^{5}b_i^2=[(-4)^2+(-2)^2+0+(2)^2+(4)^2]-[(4)^2+(2)^2+0+(-2)^2+(-4)^2]$ or, $=40-40$ or, $=0$
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