Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 30



Work Step by Step

Since, we have $\sum_{i=1}^{5}[\dfrac{(i+2)!}{i!}]=\dfrac{3!}{1!}+\dfrac{4!}{2!}+\dfrac{5!}{3!}+\dfrac{6!}{4!}+\dfrac{7!}{5!}$ $=6+12+20+30+42$ Hence, we get or, $=110$
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