Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 29



Work Step by Step

Since, we have $\sum_{i=1}^{5}[\dfrac{i!}{(i-1)!}]=\dfrac{1!}{0!}+\dfrac{2!}{1!}+\dfrac{3!}{2!}+\dfrac{4!}{3!}+\dfrac{5!}{4!}$ or, $=-1+\dfrac{1}{2}-\dfrac{1}{6}+\dfrac{1}{24}-\dfrac{1}{240}$ Hence, we get $=1+2+3+4+5$ or, $=15$
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