Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 24



Work Step by Step

Since, we have $\sum_{i=2}^{4}[\dfrac{(-1)^i}{3^i}]=[\dfrac{(-1)^2}{3^2}]+[\dfrac{(-1)^3}{3^3}]+[\dfrac{(-1)^4}{3^4}]$ or, $=\dfrac{1}{9}-\dfrac{1}{27}+\dfrac{1}{81}$ Hence, we get $=\dfrac{7}{81}$
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