Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 51



Work Step by Step

Since, we have from the graph: $\sum_{i=1}^{5}(2a_i+b_i)=[2(-4)+4]+[2(-2)+2]+[2(0)+0]+[2(2)+(-2)]+[2(4)+(-4)]$ or, $=-4-2+0+2+4$ or, $=0$
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