Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.6 Solving Quadratic Equations by Using the Quadratic Formula - 4.6 Exercises - Page 373: 64

Answer

$ p=-\frac{31}{6}$

Work Step by Step

This is a linear function. Solve for $p$. $$ \begin{aligned} -2.3(p+7) + 2 & =4.3 p+20 \\ -2.3 p-16.1+2 & =4.3 p+20 \\ -2.3 p-4.3 p & =20 +16.1-2 \\ -6.6 p & =34.1 \\ p- & =-\frac{34.1}{6.6} \\ & =-\frac{341}{66} \\ & =-\frac{31}{6}\\ &\approx -5.167. \end{aligned} $$ The solution is $$ p=-\frac{31}{6}.$$ Define the following version of the function and plot it. We see that the zero is where it should be. $$ f(p) =4.3 p+20+2.3(p+7)-2=6.6p+34.1. $$
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