Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.6 Solving Quadratic Equations by Using the Quadratic Formula - 4.6 Exercises - Page 373: 46

Answer

$v = -8, v = -6$

Work Step by Step

Use either the square root method, the quadratic formula or factoring. $$ \begin{aligned} v^2+14 v & =-48 \\ v^2+14 v+7^2 & =-48+7^2 \\ (v+7)^2 & =1 \\ v+7 & = \pm 1 \\ v & =-7 \pm 1. \end{aligned} $$ This gives: $$ \begin{aligned} &\begin{aligned} v& =-7-1 \\ & =-8 \end{aligned}\\ &\begin{aligned} v & =-7+1 \\ & =-6. \end{aligned} \end{aligned} $$ Define the following function and plot it. We see that the zeros are where they should be. $$ f(v) =v^2+14 v +48. $$
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