Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.6 Solving Quadratic Equations by Using the Quadratic Formula - 4.6 Exercises - Page 373: 52

Answer

$x = -7.59 $ or $ x= 1.79$

Work Step by Step

Multiply both sides by $10$ then use the quadratic formula. $$ \begin{aligned} 9.9 x^2+57.4 x-134.8&=0\\ 99 x^2+574 x-1348=0 \end{aligned} $$ $$ \begin{aligned} a & =99 \\ b& =574\\ d & =-1348 \\ \end{aligned} $$ $$ \begin{aligned} x&= \frac{-b\pm \sqrt{b^2-4ac}}{2a}\\ x& =\frac{-(574) \pm \sqrt{(574)^2-4 \cdot 99 \cdot (-1348)}}{2 \cdot 99 }\\ & =\frac{-574 \pm \sqrt{863284}}{198}. \end{aligned} $$ This gives $$ \begin{aligned} x & =\frac{-574 - \sqrt{863284}}{198} \\ & \approx-7.59\\ x & =\frac{-574 + \sqrt{863284}}{198} \\ & \approx1.79 \end{aligned} $$ We got: $$x = -7.59 \text{ or } x= 1.79.$$ Define the following function and plot it. We see that the zeros are where they should be. $$ f(x) =9.9 x^2+57.4 x-134.8 $$
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