Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.6 Solving Quadratic Equations by Using the Quadratic Formula - 4.6 Exercises - Page 373: 48

Answer

$d = -22, d= -12$

Work Step by Step

Use either the square root method, the quadratic formula or factoring. $$ \begin{aligned} 105 & =5(17+d)^2-20 \\ 105+20 & =5(17+d)^2 \\ 125 & =5(17+d)^2 \\ 25 & =(17+d)^2 \\ \pm \sqrt{25} & =17+d \\ \pm 5-17 & =d \end{aligned} $$ This gives: $$ \begin{aligned} d & =-5-17 \\ & =-22\\ d & =5-17 \\ & =-12. \end{aligned} $$ Define the following function and plot it. We see that the zeros are where they should be. $$ f(d) =(17+d)^2-25. $$
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