Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.6 Solving Quadratic Equations by Using the Quadratic Formula - 4.6 Exercises - Page 373: 42

Answer

$k= -4.72,k= 2.42$

Work Step by Step

Use the square root method. Use the quadratic formula. $$ k^2+2.3 k-11.4=0. $$ $$ \begin{aligned} & a=1 \\ & b=2.3 \\ & c=-11.4 \end{aligned} $$ $$ \begin{aligned} k & =\frac{-b \pm \sqrt{b^2-4 a c}}{2 a} \\ & =\frac{-2.3 \pm \sqrt{2.3^2+4 \cdot 11.4}}{2} \\ & =\frac{-2.3 \pm \sqrt{50.89}}{2} \\ & \approx \frac{-2.3 \pm 7.1337}{2} \end{aligned} $$ $$ \begin{aligned} k & =\frac{-2.3-7.1337}{2} \\ & =-4.72 \end{aligned} $$ $$ \begin{aligned} k& =\frac{-1.4+7.846}{2} \\ & =2.42 \end{aligned} $$ Define the following version of the function and plot it. We see that the zeros are where they should be. $$ h(k) =k^2+2.3 k-11.4$$
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