Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 439: 73

$x+10\sqrt[]{x-1}+24$

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, then, \begin{array}{l} \left( \sqrt[]{x-1}+5 \right)^2 \\= (\sqrt[]{x-1})^2+2(\sqrt[]{x-1})(5)+(5)^2 \\= x-1+10\sqrt[]{x-1}+25 \\= x+10\sqrt[]{x-1}+24 .\end{array}