Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 439: 51

Answer

$3\sqrt{x}-x\sqrt{3}$

Work Step by Step

Using the Distributive Property and the properties of radicals, then, \begin{array}{l} \sqrt{3x}\left( \sqrt{3}-\sqrt{x} \right) \\= \sqrt{9x}-\sqrt{3x^2} \\= \sqrt{9\cdot x}-\sqrt{x^2\cdot3} \\= 3\sqrt{x}-x\sqrt{3} .\end{array}
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