Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 439: 55

Answer

$\sqrt[3]{a^2}+\sqrt[3]{a}-20$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL method, then, \begin{array}{l} \left( \sqrt[3]{a}-4 \right)\left( \sqrt[3]{a}+5 \right) \\= (\sqrt[3]{a})(\sqrt[3]{a})+(\sqrt[3]{a})(5)+(-4)(\sqrt[3]{a})+(-4)(5) \\= \sqrt[3]{a^2}+5\sqrt[3]{a}-4\sqrt[3]{a}-20 \\= \sqrt[3]{a^2}+\sqrt[3]{a}-20 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.