Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 439: 66

Answer

$y-6x\sqrt[]{y}+9x^2$

Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, then, \begin{array}{l} \left( \sqrt[]{y}-3x \right)^2 \\= (\sqrt[]{y})^2+2(\sqrt[]{y})(-3x)+(-3x)^2 \\= y-6x\sqrt[]{y}+9x^2 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.