Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 439: 63

Answer

$x-y^2$

Work Step by Step

Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, then, \begin{array}{l} \left( \sqrt[]{x}-y \right)\left( \sqrt[]{x}+y \right) \\= (\sqrt[]{x})^2-(y)^2 \\= x-y^2 .\end{array}
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