Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 439: 56

Answer

$\sqrt[3]{a^2}+9\sqrt[3]{a}+14$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL method, then, \begin{array}{l} \left( \sqrt[3]{a}+2 \right)\left( \sqrt[3]{a}+7 \right) \\= (\sqrt[3]{a})(\sqrt[3]{a})+(\sqrt[3]{a})(7)+(2)(\sqrt[3]{a})+(2)(7) \\= \sqrt[3]{a^2}+7\sqrt[3]{a}+2\sqrt[3]{a}+14 \\= \sqrt[3]{a^2}+9\sqrt[3]{a}+14 .\end{array}
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