Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 439: 71

Answer

$x+1$

Work Step by Step

Using $a^3\pm b^3=(a\pm b)(a^2\mp ab+b^2)$, then, \begin{array}{l} \left( \sqrt[3]{x}+1 \right)\left( \sqrt[3]{x^2}-\sqrt[3]{x}+1 \right) \\= (\sqrt[3]{x})^3+(1)^3 \\= x+1 .\end{array}
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