Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 439: 69

Answer

$-\sqrt[3]{4}+2\sqrt[3]{2}$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL method, then, \begin{array}{l} \left( \sqrt[3]{4}+2 \right)\left( \sqrt[3]{2}-1 \right) \\= (\sqrt[3]{4})(\sqrt[3]{2})+(\sqrt[3]{4})(-1)+(2)(\sqrt[3]{2})+(2)(-1) \\= \sqrt[3]{8}-\sqrt[3]{4}+2\sqrt[3]{2}-2 \\= 2-\sqrt[3]{4}+2\sqrt[3]{2}-2 \\= -\sqrt[3]{4}+2\sqrt[3]{2} .\end{array}
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